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  1. #1
    This comment is witty! Senior Member LittleGrizzly's Avatar
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    Default Physics

    Seems like the best place to put this,
    I have a test coming up on circular motion and i would like one of you guys to check over my answers as i missed a few of the lessons we had on it so the teacher gave me a quick half hour run through of it, i think i mostly get it but i want to make sure im not messing anything easy up.
    1. The planet venus can be assumed to orbit the sun in a circular orbit whose radius is 1.08 x 10 (11) m (in brackets is to the power of). The mass of the sun is 2.00 x 10 (30) kg
    write down an expression for
    (i) the gravitational force on venus
    (ii) the centripetal force required to act on venus to enable it to travel in a circularorbit. Use the fact these two expressions represent the same force to calculate the angular velocity of venus in its orbit.
    Use the angular velocity to determine
    a) the linear velocity of venus and
    b) the period of the orbit of venus.
    express your answer to b) in days
    and heres my answers...

    1i) F = G (m1 x m2 / r (2) )
    Force = Gravitation constant x mass of object 1 x mass of object 2 / distance between object centres

    ii) F= m2 r w (2)
    Force = mass of object 2 x radius x angular velocity (2)

    m2 x r x w (2) = G x m1 x m2 / r (2)
    m2 (mass of venus) cancels leaving

    r x w (2) = G x m1 / r (2)
    (1.08 x 10 (11) ) x w (2) = (6.67 x 10 (-11) ) x (2.00 x 10 (30) ) / (1.08 x 10 (11) )
    (1.08 x 10 (11) ) x w (2) = 0.01143689986

    w (2) = 1.05897221 x 10 (-13)
    w = 3.25418532 x 10 (-7)

    a) v = r x w
    v = 1.08 x 10 (11) x 3.25418532 x 10 (-7)
    v = 35145.20146 ms - 1

    b) T = 2pi/w
    Time = 2 x pi (3.14) / angular velocity

    Time = 19298224.85 seconds
    321637.0808 minutes
    5360.918013 hours
    223.3590839 days orbit for venus around the sun
    Last edited by LittleGrizzly; 05-19-2008 at 17:15.
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