
Originally Posted by
Hax
Just one moment, please.
Half of the regular troops, would of course be 180,000 men. In total counting (3 x 60,000) x 2 = 180,000 x 2 = 360,000.
However, keep in mind that not all of the soliders were stationed in Thermopylae at that time, as some were I believe in Thrace, or with the fleet at Salamis. There are some other interesting things Olmstead states in his book, such as:
(400 x 3) [three meals per day] x 60 [calculation to minai] = 72,000 [mnai for meals] 0.2 (or 20 drachmae). Well, 20 ancient drachmae per soldier was more than enough to feed a standing army of 360,000 men, especially when thinking of supplies and such. So I guess 360,000 men is probably a good bet.
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