Land battles FAQ

[CBR]

Hm so is it 1.4 km² or 1.4x1.4 km?


CBR

[Megas Methuselah]

Good question. I await an answer, although I would imagine it would be 1.4k x 1.4k. That's sweet.

[hoom]

The current mechanism assumes that the battlefield chosen is the best that could be attained as a result of manoeuvre and counter manoeuvre of opposing forces and the limits of terrain in the area.

Was not particularly happy with the answer here.
At least in the RTW engine, you could place your army on a hill on the campaign map, expecting a battle to have your army sitting on a hill & the enemy on the down face, only to find yourself on the downside facing up to the attacking army sitting on your hill!

[Polemists]

So this isn't like MTW 2 where if I get attacked on a bridge the battle takes place with some land, a bridge, and a river?

I don't get how the counter thing is diff then MTW 2 but then again I don't really get it camera angle discussions

[Jack Lusted]

Hm so is it 1.4 km² or 1.4x1.4 km?

As I said 1.4km x 1.4km.

[Monsieur Alphonse]

Good news. Although 1.4*1.4 is almost 2km2

[CBR]

As I said 1.4km x 1.4km.

Thanks.

Yes 2 km² maps are a good improvement although it depends a bit on artillery range. It does not take much before a centrally placed battery position can dominate most of the map.


CBR

[Alerion]

afaik the lightest artillery of that time (with the highest range) had a range of about 600 metres...

[Sheogorath]

The British were not always the best at everything.

Haha! Confirmation from CA!
'Tis a glorious day!

[hoom]

afaik the lightest artillery of that time (with the highest range) had a range of about 600 metres...

Which means that a unit in the middle of a 1400 * 1400 map dominates a 1200m diameter area...

[Sheogorath]

Which means that a unit in the middle of a 1400 * 1400 map dominates a 1200m diameter area...

Of course, I dont think you're going to find many perfectly flat battlefields.
Knowing CA, we're probably still going to encounter the occasional 'Giant hillside, where the player is at the bottom and the AI is at the top. Also, there's a forest covering the entire map.' map.

[fenir]

I couldn't help myself, I luaghed and laughed.

1.4km², is that 1.4 km x 1.4 km?...........roflmao.

too funny. 1.4 x 1.4 = 1.4². lol


so 1.4 x 1.4 = 1.96 which is 1.4² We find this by taking the square root of 1.96, which = 1.4²

So essentially, i think this would be the converse of pythagoras, a² x b² = c²

So from here we can work out if the trianlge is , right, acute, or obtuse.

If,
a² x b² = c² it is a right angle, trianlge.

a² x b² > c² , then it's a acute triangle.

a² x b² < c² , then it's a obtuse trianlge.

Which then moves on to produce, the law of consines. Where we can represent, a + b -2ab cosΦ = c²


Or we can do it the longway, in cartesian coordinates. (which in it's self is a part of the pythagroas theorm.

(x0, y0) (x1, y1) are points, which are a and b, each having it's own coordinates.

SO "x" being the being teh axis horizontal, and "y" is the vertical axis.

So if we take,


(x1 - x0)² + (y1 - y0)² = φ Where φ is the variable of the function.

Then complete the square root. you will have your distance between,two points, so this first one, will only complete the "a" lenght.

You will then have to take the two points for "b". Then you will ahe your points
I suppose we could have done some euclicdian n Spacem but that takes longer.

It all really means, Is that given two sets of points. on the xy axis. We can move to work out the distance between two points.
ONce we have the distance, say a and b, when can then work out hypothenuse.
Once with ahve the hypothenuse, then can then work out the inside angles, by using the cosine rule.


Ahhh i could go on all day with this one, but i see many of you are already asleep.

sincerely

fenir