Assume each bullet is 50g and spherical.
Density of stone (granite in this case) = 2.75 g/cm3, Density of Lead = 11.34 g/cm3
Therefore: Volume of Stone bullet = 50/2.75 = 18.18cm3, Volume of Lead bullet = 50/11.34 = 4.41cm3
Using Volume of a sphere =
we get R(Stone) = 1.63cm, R(Lead) = 1.02cm
can use this to calculate the cross sectional area of each projectile: A(Stone) = 8.04cm2, A(Lead) = 3.27cm2
and input into this equation for drag resistance.

for simplicity p (air density) and Cd (drag coefficient) are taken as = 1 as both would be the same for each projectile
set velocity (v) to 30m/s
F(Stone) = 3618N, F(Lead) = 1472N (note these are not the actual forces its just done to compare the ratio of forces felt)
From this we see that the air resistance on the stone is almost 2.5 times greater than the lead bullet and so would slow down quicker.
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