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  1. #1
    ‘Abdü’l-Mecīd-i evvel Member Kival's Avatar
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    Default Re: Logic

    Quote Originally Posted by Kival View Post
    Pr(E | H) = Pr(H ∩ E)/Pr(H) (Definition of baysian probability)
    => Pr(H ∩ E) = Pr(E | H)*Pr(H) (just simple transformation)

    As Pr(E | H) has a value range in the interval [0;1] (it's a probability function), obviously it follows:

    Pr(H ∩ E) <= Pr(E | H)*Pr(H)

    Because of Pr(H | E)=Pr(H ∩ E)/Pr(E), the second part of a) follows trivially.
    From the above you can agree on:

    Pr(H ∩ E) = Pr(E | H)*Pr(H) ?

    Now just remember, what you know about the Pr-function. It's a function which gives you the probabilty of an event. The event is described as a set or as a logical combination of events. What do you know in general about the probability function? It has only values between 0 and 1. So 0<=Pr(A)<=1 for all possible events A. In mathematical detail, Pr(. | B), the baysian probability function is an own function but it's still a probability function and so it still has only values from 0 to 1. If you multiply Pr(H) with a value between 0 and 1, it can only be Pr(H) or smaller.

    ‘Abdü’l-Mecīd-i evvel

  2. #2
    One of the Undutchables Member The Stranger's Avatar
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    Default Re: Logic

    ah... if u put it like that it seems simple XD

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  3. #3
    Senior Member Senior Member Reenk Roink's Avatar
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    Default Re: Logic

    First hard homework in your philosophy major career TS?

  4. #4
    One of the Undutchables Member The Stranger's Avatar
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    Default Re: Logic

    omg yes... first 2 years i was cruising, now im in some rough waters, the courses are really challenging and this tops it till now :P. I wish i had more time, but it seems like i am trying to do too much stuff :P

    tho really thank you Kival, you actually made me understand it haha, appreciated.
    Last edited by The Stranger; 12-13-2011 at 17:26.

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  5. #5
    ‘Abdü’l-Mecīd-i evvel Member Kival's Avatar
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    Default Re: Logic

    Quote Originally Posted by The Stranger View Post
    tho really thank you Kivak, you actually made me understand it haha, appreciated.
    It's Kival, but you're welcome. ;-)

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  6. #6
    One of the Undutchables Member The Stranger's Avatar
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    Default Re: Logic

    typo :P

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