I got it through applying algebra to your data. I'm sure I don't have to explain the exact steps to you—I started with y = ax + b (where y is the corruption percentage, b is the "grace distance," and x is the distance minus grace distance), plugged in data, and solved for b. (Actually, I was only doing proportions, so the coefficient a cancelled out.) I may have been excessively precise, but the number did seem to be a very precise fit.
For example, let's take the ratio of corruption at 20 squares to corruption at 40 squares. You give the former as 0.0333958 and the latter as 0.195592, so the ratio is about 0.1707. Since we're talking about a line, this ratio should be exactly the same as (20 – b) / (40 – b). If we use 15.88, we get a ratio of 4.12 / 24.12, or about 0.1708. Repeat with the ratios of 60 squares to 35 squares, which should be 0.357788 / 0.155043, or 2.308. The ratio should be 44.12 / 19.12, which equals 2.308. It's pretty strange, but there you have it.
-Simetrical
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