ROME-Calculator

[Sebastianfog]

Hi!

We have programmed the tool ROME-Calculator.
The version 1.00a ist available under:
http://www.totalwar.org/Downloads/Rt...or_v.1.00a.zip

With this program you are able to calculate how much turns it needs to arrive a population "x", in one of your citys.
For that you have to type in your current population, the estimated population (the population you want to arrive) and the growth rate of your town. As the result the program shows you the estimated turns (for more read the Readme.txt in the zip-folder).

Our plan is to implementate more things into the program, e.g. that you also can search which population you have to estimate, under determined turns. Another target is to make you able, to calculate the estimated turns for a determined population, with the option that the growth rate is not constant, because of hunger or something else. So that there is not, like it is yet, a (not so realistic) constant growth rate. The greater target is to give you the ability, to calculate the growth rate of your whole empire within all what influences this. The last point will take longer than the others, because for this you need higher mathematical terms.

So we want you to inform with this thread, that the work on this program goes on and that you know what you have to await. But we also like to hear your opinions and what you think about this program and what your wishes are. So that we can see if we can implementate them.

Greetings from Sebastianfog
and my brother (ORCILLER)! ;)

[tombom]

Hmmm... you say that this is distrubuted under the gnu liscence, but you provide no source and you say this can only be uploaded here.

Otherwise, interesting tool.

[Alexandr III. Biges]

Good utility.

And to some more advaced, you may calculate it yourselves with any standard calculator:

x - turns needed to pop. increase
T - target population
C - current population
g - growth rate as a decimal number
ln - natural logarithm
^ - power (mat.)

C * ( 1 + g )^x = T
( 1 + g )^x = T - C
x * ln ( 1 + g ) = ln ( T - C )
therefore:

x = ln ( T - C ) / ln ( 1 + g )

Enjoy :)

[Alexanderofmacedon]

Very cool!