Quote Originally Posted by A.Saturnus
He didn´t say 27% chance on the third attempt, but that chance with three attempts.
The chance of failure for one attempt is 0.9. For two attempts 0.9*0.9 and for three attempts 0.9*0.9*0.9=0.73.
Maybee my understanding of English is really bad but how can you sum it up like that? First attempt 9%, 2nd 9%, 3rd 9% etc etc you can´t add each chance togheter to increase your chances. Then the math would look like this: 9/100, 18/200 and 27/300 = 9% each time, right?
Or do he mean that using three different spies at the same time will actually increase the chances of killing a vic? So if I use 10 spies making 10 attempts at the same time I will actually have a 90% chance. This can´t be right.