think about it this way. List out all the possible outcomes
On a 2 assassination attempt there are 4 results
SF
SS
FS
FF
So to have a successful assasination in 2 attempts, you would either have to have SF, FS, or SS. What are the chances of those? You alraedy know that the chance of succeeding on the first attempt is 10%. And on the case that the first one don't succeed (90%), you could still be successful by succeeding on the second try, and the possiblity of that is 0.9 x 0.1, which is 0.09. Add them up, you get 0.19 (19%)
You could do that with 3 attempts too, but if you notice, the chance of success is just 1 minus the probability of failing every attempt, since you fail the assassination if you don't succeed on every attempt. So on a 3 attempt assasination, it'll just be 1 - (0.9^3), which is 0.271
But, I don't think the assassination possibility is very accurate. I think it's more of a arbitrary value. I've had a success rate of 50%, but after 30 attempts with reloading, he still fails everytime. I think the computer determine whether the assassination would be successful before you could actually attempt it, so the number actually mean nothing because the computer already determined whether you would succeed or not.
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