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  1. #1
    Member Member Alexander the Pretty Good's Avatar
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    Default Re: Maths question

    Better yet, take the integral of f(x) = x^2 for the interval [0, 2^10000].

    What does your calculator say about that?

  2. #2
    Master of useless knowledge Senior Member Kitten Shooting Champion, Eskiv Champion Ironside's Avatar
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    Default Re: Maths question

    Quote Originally Posted by Alexander the Pretty Good
    Better yet, take the integral of f(x) = x^2 for the interval [0, 2^10000].

    What does your calculator say about that?
    It says 2,646967839710986774710839276339*10^9030
    And I was using my own calculator not the windows version (except to get all the decimals in the end, can "only" get 10 on my own calc).

    BTW the windows calculator can handle numbers up to something in between 10^43429 and 10^43430.
    If 10^3010 is insanely big, what's 10^43429 then?
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  3. #3
    Just another genius Member aw89's Avatar
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    Default Re: Maths question

    Insanely big + 40419


  4. #4
    Arena Senior Member Crazed Rabbit's Avatar
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    Default Re: Maths question

    Wow. That is a big number. My calc (A high-end 3d graphing calculator) will only do powers of 2 up to 3321.9280948873999999. Trying to do 2 to the power of 3321.9280948874 will give me infinity.

    Crazed Rabbit
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