Quote Originally Posted by The_Mark
I'm just about to graduate from the Finnish equivalent of high school
I hope the you get the results you wanted. I've got half a year left of my schooling.

Quote Originally Posted by The_Mark
The bowl assignment doesn't sound that difficult.
It's just a bit confusing.
V = π∫ a/2 to a (a^2 - y^2) dy
= π [(a)^3/3 - (y)^3/3] a/2 to a
= π/3 {a^3 - (3(a)^3)/8 - a^3 + (8(a)^3)/8}
= π/3 {(5(a)^3)/8}
= (5π(a)^3)/24

Quote Originally Posted by Avicenna
Forcing you to do it by integration is evil.
But strangely satisfying if you get it right.