I hope the you get the results you wanted. I've got half a year left of my schooling.Originally Posted by The_Mark
It's just a bit confusing.Originally Posted by The_Mark
V = π∫ a/2 to a (a^2 - y^2) dy
= π [(a)^3/3 - (y)^3/3] a/2 to a
= π/3 {a^3 - (3(a)^3)/8 - a^3 + (8(a)^3)/8}
= π/3 {(5(a)^3)/8}
= (5π(a)^3)/24
But strangely satisfying if you get it right.Originally Posted by Avicenna
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