Maths question

**Uesugi Kenshin** · 02-08-2006, 04:27

Okay, here's my suggestion. Don't teach people that don't want to be taught math past exponents, quadratics and the beginnings of imaginary numbers. Most students here don't get to that, much less past it. And I certainly will never use what I am learning now ever again, except in classes of course.

I'd rather be slightly unbalanced than have a chance to get a C in Honors pre-calc....

**Duke of Gloucester** · 02-08-2006, 07:51

I don't know. I am assuming that your maths teacher knows that you can't do that sum on a standard calculator and is expecting you to use some maths to work out this answer. How about:

2^10 = 1024

so 2^10000 = 1024^1000
= 1000^1000 x 1.024^1000
= 10^3000 x 1.024^1000

Now 1.024^1000 can be done on a normal calculator. It equals 2.00 x 10^10 to 3 sig. fig..

Therefore 2^10000 = 2.00 x 10^3010 calculated on a normal calculator using a little ingenuity.

**ajaxfetish** · 02-08-2006, 08:47

And now I feel the effects of not having taken a math class in the last five years. When I was taking AP Calc I was on top of the world; now the good Duke's post is complete gibberish to me.

Ajax

**Ironside** · 02-08-2006, 10:41

2^10000= 10^(lg2*10000)= 10^3010.2999566398119521373889472449
If your teacher doesn't like that answer

pick up the decimals of lg2*10000=3010.x

so you get 10^0.x = 1.9950631168807583848837421626836

Thus you get 1.9950631168807583848837421626836*10^3010

Haven't anyone here learned to count with logaritmes?