Results 1 to 20 of 20

Thread: Logic

Hybrid View

Previous Post Previous Post   Next Post Next Post
  1. #1
    ‘Abdü’l-Mecīd-i evvel Member Kival's Avatar
    Join Date
    Aug 2009
    Location
    Hamburg, Germany
    Posts
    767

    Default Re: Logic

    Oh, sorry, I did not want to ask if you have a degree, only if you know enough set theory. Okay, ignore my mistakes in english, I hope you can understand the ideas:

    Okay let's work with set theory then. a is actually quite trivial but I'll try to give you an idea how to prove it:


    Pr(E | H) = Pr(H ∩ E)/Pr(H) (Definition of baysian probability)
    => Pr(H ∩ E) = Pr(E | H)*Pr(H) (just simple transformation)

    As Pr(E | H) has a value range in the interval [0;1] (it's a probability function), obviously it follows:

    Pr(H ∩ E) <= Pr(E | H)*Pr(H)

    Because of Pr(H | E)=Pr(H ∩ E)/Pr(E), the second part of a) follows trivially.

    for b) you just need the equations and knew two things:

    H → ¬E -> (H ∩ E) = {} and Pr ( {} )=0 ({} being the empty set)

    c) Obviously (H ∩ E) and (H^(c) ∩ E) are disjoint sets, so you can use Sigma additivity (H^(c) being the complement of H) . Do you know where to go from there?
    Last edited by Kival; 12-13-2011 at 02:50.

    ‘Abdü’l-Mecīd-i evvel

  2. #2
    One of the Undutchables Member The Stranger's Avatar
    Join Date
    Dec 2004
    Location
    Nowhere...
    Posts
    11,757

    Default Re: Logic

    i get B and C.

    I still dont get A however, why is the probability of (H&E) smaller or the same as the probability of (H)?

    We do not sow.

  3. #3
    ‘Abdü’l-Mecīd-i evvel Member Kival's Avatar
    Join Date
    Aug 2009
    Location
    Hamburg, Germany
    Posts
    767

    Default Re: Logic

    Quote Originally Posted by Kival View Post
    Pr(E | H) = Pr(H ∩ E)/Pr(H) (Definition of baysian probability)
    => Pr(H ∩ E) = Pr(E | H)*Pr(H) (just simple transformation)

    As Pr(E | H) has a value range in the interval [0;1] (it's a probability function), obviously it follows:

    Pr(H ∩ E) <= Pr(E | H)*Pr(H)

    Because of Pr(H | E)=Pr(H ∩ E)/Pr(E), the second part of a) follows trivially.
    From the above you can agree on:

    Pr(H ∩ E) = Pr(E | H)*Pr(H) ?

    Now just remember, what you know about the Pr-function. It's a function which gives you the probabilty of an event. The event is described as a set or as a logical combination of events. What do you know in general about the probability function? It has only values between 0 and 1. So 0<=Pr(A)<=1 for all possible events A. In mathematical detail, Pr(. | B), the baysian probability function is an own function but it's still a probability function and so it still has only values from 0 to 1. If you multiply Pr(H) with a value between 0 and 1, it can only be Pr(H) or smaller.

    ‘Abdü’l-Mecīd-i evvel

  4. #4
    One of the Undutchables Member The Stranger's Avatar
    Join Date
    Dec 2004
    Location
    Nowhere...
    Posts
    11,757

    Default Re: Logic

    ah... if u put it like that it seems simple XD

    We do not sow.

  5. #5
    Senior Member Senior Member Reenk Roink's Avatar
    Join Date
    Oct 2005
    Posts
    4,353

    Default Re: Logic

    First hard homework in your philosophy major career TS?

  6. #6
    One of the Undutchables Member The Stranger's Avatar
    Join Date
    Dec 2004
    Location
    Nowhere...
    Posts
    11,757

    Default Re: Logic

    omg yes... first 2 years i was cruising, now im in some rough waters, the courses are really challenging and this tops it till now :P. I wish i had more time, but it seems like i am trying to do too much stuff :P

    tho really thank you Kival, you actually made me understand it haha, appreciated.
    Last edited by The Stranger; 12-13-2011 at 17:26.

    We do not sow.

  7. #7
    ‘Abdü’l-Mecīd-i evvel Member Kival's Avatar
    Join Date
    Aug 2009
    Location
    Hamburg, Germany
    Posts
    767

    Default Re: Logic

    Quote Originally Posted by The Stranger View Post
    tho really thank you Kivak, you actually made me understand it haha, appreciated.
    It's Kival, but you're welcome. ;-)

    ‘Abdü’l-Mecīd-i evvel

  8. #8
    One of the Undutchables Member The Stranger's Avatar
    Join Date
    Dec 2004
    Location
    Nowhere...
    Posts
    11,757

    Default Re: Logic

    typo :P

    We do not sow.

Bookmarks

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts
  •  
Single Sign On provided by vBSSO